How can I check if a list is a superset of another list in Python without using set()?
Alex K

To check if one list is a superset of another list in Python without using theset() function, you can implement a custom solution by comparing the elements of the lists. Here's a long-form explanation of one possible approach: 1. Determine the Lists: - Begin by identifying the two lists you want to compare. Let's refer to them aslist1 (potential superset) andlist2 (potential subset). 2. Create a Superset Checker Function: - Define a function, let's call itis_superset, that takeslist1 andlist2 as arguments and checks iflist1 is a superset oflist2. - Inside the function, iterate over each element inlist2 using afor loop. - For each element, check if it exists inlist1. - If an element inlist2 is not found inlist1, returnFalse as it indicates thatlist1 is not a superset oflist2. - If all elements inlist2 are found inlist1, continue iterating until the end oflist2. - If the loop completes without returningFalse, it means that all elements inlist2 are present inlist1, andlist1 is a superset oflist2. In this case, returnTrue. - Example:

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def is_superset(list1, list2):
    for element in list2:
   if element not in list1:
  return False
    return True

3. Call the Superset Checker Function: - Now, you can call theis_superset function, passinglist1 andlist2 as arguments, to check iflist1 is a superset oflist2. - Assign the returned value to a variable for further processing or printing. - Example usage:

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list1 = [1, 2, 3, 4, 5]
list2 = [3, 5]
is_superset_result = is_superset(list1, list2)
print(is_superset_result)  # Output: True

By implementing theis_superset function, you can check iflist1 is a superset oflist2 without utilizing theset() function. The function iterates over each element inlist2 and checks if it exists inlist1. If all elements are found, it returnsTrue; otherwise, it returnsFalse.

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